Equation of line passing through given points :
Let's proceed with two point form ~
Assume :
So, the equation of required line is : y = 3 ~
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1 answer:
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Answer:
Step-by-step explanation:
Consider a sketch of the problem as shown in the picture, where:
- Blue line is given by y = 4x + 1.
- Point B is the center of the circle.
- Point A is (-3, 0).
Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.
So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.
Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by
then with h = -3, k = -11 and r= 11, the equation of our circle is
Answer:
x = 3
Step-by-step explanation:
Given
4 : 8 = x : 6, expressing in ratio form, that is
=
( cross- multiply )
8x = 24 ( divide both sides by 8 )
x = 3
Thus 4 : 8 = 3 : 6