Find the limit if it exists

Mathematics

1 answer:

mash [69]2 years ago

3 0

Answer:

20.

Step-by-step explanation:

When x = 2

f(x= 3(2)^3 + 2^2 - 8

= 24 + 4 - 8

= 20.

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A.
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B.
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C.
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D.
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Given:
A has coordinates (-6,5)
C has coordinates (3.6,-0.4).
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Refer to the diagram shown below.
The coordinates of B are determined by
$\frac{3.6-(-6)}{x-(-6)} = \frac{3}{3+2} \\ \frac{9.6}{x+6} = \frac{3}{5} \\ 3(x+6) = 48 \\ 3x +18=48 \\ x=30/3=10$
Also,
$\frac{5-(-0.4)}{5-y} = \frac{3}{5} \\ 3(5-y) = 27 \\ 15-3y=27 \\ y= \frac{12}{-3} =-4$

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The coordinates of B are (10,-4).

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Answer:
The coordinates of D are (1.11, 1)

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