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Marina86 [1]
3 years ago
5

Write the equation y=3/4x-4 in standard form

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

-3x+4y=-16

Step-by-step explanation:

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One factor of the polynomial 6x3 − x2 + 8x + 5 is (2x + 1). What is the other factor of the polynomial? (Note: Use long division
maria [59]

Answer:

(3x^2 - 2x + 5)

Step-by-step explanation:

3x^2 - 2x + 5

2x + 1 \sqrt{6 {x}^{3}  -  {x}^{2}  + 8x + 5  }

- <u>(6x^3 + 3x^2)</u>

-4x^2 +8x +5

- <u>(-4x^2 - 2x)</u>

10x + 5

-(<u>10x + 5)</u>

00

(2x+1) (3x^2 - 2x + 5) = 6x^3 - x^2 + 8x + 5

Therefore the other factor of the polynomial is (3x^2 - 2x + 5)

4 0
3 years ago
Read 2 more answers
Given f(x)=x2+12x+26. Enter the quadratic function in vertex form in the box. f(x)=
makvit [3.9K]

Answer:

vertex(-6,-3)

Step-by-step explanation:

x^2+12+36-36+26

(x+6)^2-10

v=(-6,-10)

4 0
3 years ago
Help! <br> Which expression is equivalent? <br> On edge
Ira Lisetskai [31]

Answer: Choice B

x^{1/8}y^{8}

======================================================

Explanation:

The two rules we use are

(a*b)^c = a^c*b^c

(a^b)^c = a^{b*c}

When applying the first rule to the expression your teacher gave you, we can say that:

\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}

Then applying the second rule lets us say

\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}

Therefore,

\left(x^{1/4}y^{16}\right)^{1/2}  = x^{1/8}y^{8}

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

7 0
3 years ago
I WAS ONLY ABLE TO SELECT 40 PTS THIS TIME, PLS ANSWER THIS ONE IT HAS THE PICTURE WITH IT.
BaLLatris [955]
Okay so the first one is right.
The second one is wrong.
the third one is right.
The forth one is wrong.
4 0
3 years ago
Read 2 more answers
Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
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