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Rina8888 [55]
2 years ago
14

I need help with my math can you help me ​

Mathematics
1 answer:
MrRissso [65]2 years ago
3 0

Answer:

what's the question? ???

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On monday marco practiced the piano for 7/10 hour. On Tuesday he practiced for 1 1/4 hours each day write a question that involv
Fantom [35]

Step-by-step explanation:

Since we have given that

Number of hour Marco practiced the piano on Monday is given by

\frac{7}{10}

Number of hours Marco practiced the piano on Tuesday is given by

1\frac{1}{4}=\frac{5}{4}\ hours

1) For Adding :

Total number of hours he practiced on both Monday and Tuesday will be

\frac{7}{10}+\frac{5}{4}\\\\=\frac{14+25}{20}\\\\=\frac{39}{20}\ hours

2) For Subtraction,

Number of hour he practiced more on Tuesday than on Monday will be

\frac{5}{4}-\frac{7}{10}\\\\=\frac{25-14}{20}\\\\=\frac{9}{20}\ hours


4 0
3 years ago
Read 2 more answers
Wright a variable expression for the word phrase, "the product of a number z and 7" A: 7 - z
drek231 [11]
Product means to multiply so, C
3 0
2 years ago
What value of x makes this equation true?<br> 5-2(x + 8) = 6x + 7
zhuklara [117]

Answer:

x = negative 9/4

Step-by-step explanation:

-2x-11=6x+7

-2x-11+11=6x+7+11

-2x=6x+18

-2x-6x=6x+18-6x

-8x=18

4 0
2 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
Anyone want to help me out?
zhuklara [117]
First answer haha~ I think I answered all your questions so far ;)
5 0
3 years ago
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