Answer:
The range of the function is:
Range R = {14, 17, 20}
Step-by-step explanation:
Given the function
We also know that range is the set of values of the dependent variable for which a function is defined.
In other words,
- Range refers to all the possible sets of output values on the y-axis.
We are given that the domain of the function is:
Domain D = {4, 5, 6}
Now,
substituting x = 4 in the function
f(4) = 3(4) + 2
f(4) = 12 + 2
f(4) = 14
substituting x = 5 in the function
f(5) = 3(5) + 2
f(5) = 15 + 2
f(5) = 17
substituting x = 6 in the function
f(6) = 3(6) + 2
f(6) = 18 + 2
f(6) = 20
Thus, we conclude that:
at x = 4, y = 14
at x = 5, y = 17
at x = 6, y = 20
Thus, the range of the function is:
Range R = {14, 17, 20}
The previous question I answered was exactly like this.
6(4) - 2(6) = 12.
K = 4.
Answer:
The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.
The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.
It is provided that the family has invested in <em>n</em> = 10 different real estate properties.
Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:
Now the lowest 80% of the amount invested can be represented as follows:
The value of <em>z</em> is 0.84.
*Use a <em>z</em>-table.
Compute the value of the mean amount invested as follows:
Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Answer:-12, -10, -3.5, 6, 11
Step-by-step explanation:
Answer:
5.46π cm³
Step-by-step explanation:
Volume of sphere= 4/3πr³
= 4/3×π×(1.6)³ cm³
=5.46π cm³
hope this helped you!
