Answer: 8 : 6
Step-by-step explanation:
Answer: 3
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Step-by-step explanation: because of the decimal you have to place a zero regardless and the other 2 zeros you can’t do anything with them. Hope this helps!
Well you are given the equation so let's plug in for kaylib and see how many miles she can see
distance = sqrt [(3 * height) / 2]
d = sqrt [(3 *48) / 2]
d = sqrt (144 / 2)
d = sqrt (72)
d = sqrt (3 * 3 * 2 * 2 * 2)
d = 6 * sqrt (2)
You you did not list Addisons height but I will say she is at x feet above sea level. we plug in x for height:
d = sqrt [(3x) / 2]
It it says how much farther for Addison which means she can see farther. to find difference we just subtract kaylibs distance from Addison. so:
sqrt [(3x) / 2] - 6 * sqrt (2)
plug in your x and use a calculator to get a decimal approximation
(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15