Answer:
There are not 15 failures and 15 successes. A confidence interval can be computed by adding 2 failures and 2 successes .
Step-by-step explanation:
Given that
Survey asked by 40 people
6 said that they were very concerned.
So the following statements correctly describe the above problem
The correct statement is , There are not 15 failures and 15 successes. A confidence interval can be computed by adding 2 failures and 2 successes .
Answer: 17 shifts each day
Step-by-step explanation:12 3/4 decided by 3/4 is 17
Answer:
60
Step-by-step explanation:
you add what he needs to make in total up ten dollars for the cupcake tin and the thirty five dollars for the profit he wants to make then I used the guess and check strategy knowing that 100 cupcakes would make him 75 dollars I worked my way down multiplying 0.75 times 90, 80, 70 and then landed on the answer 60
The trick here is to relate the NUMBER of coins to each other in one equation, and then the VALUE of the coins in another equation. If I have 1 dime, that 1 dime is worth 10 cents. The number of dimes is obviously not equal to the value. Let's call quarters q and dimes d. The number of these 2 types of coins added together is 80 coins. So q + d = 80. Now, we know that quarters are worth .25 and dimes are worth .1, so we express a quarter's worth as .25q; we express a dime's worth as .1d. The value of the coins we have is 14.90. So that equation is .25q + .1d = 14.90. Let's solve the first equation for q. q = 80 - d. We can now use that as a substitution for q into the second equation, giving us an equation with only 1 unknown, d. .25(80-d) + .1d = 14.90. Distributing through the parenthesis we have 20 - .25d + .1d = 14.90. Combining like terms gives us - .15d = - 5.1. We will divide both sides by - .15 to get that the number of dimes is 34. If we had a total of 80 coins, then the number of quarters is 80 - 34, which is 46. 46 quarters and 34 dimes
