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2 years ago

2.516x-4)=104 (1:5+0.5x)

Mathematics

1 answer:

Andre45 [30]2 years ago

5 0

Answer:

x= 42.92527821

Step-by-step explanation:

2.156x-4 = 104

x would be

42.92527821

_______________________________________________________

(1:5+0.5x)

and nothing farther can be done with this one

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franklin school has 3 boys for every 4 girls in the fifth grade. there are 140 students in the 5th grade. How many boys are ther

marin [14]

Answer:

There are 60 boys and 80 girls in Franklin School.

Step-by-step explanation:

"franklin school has 3 boys for every 4 girls in the fifth grade." means that the ratio of boys to girls is: 3:4

It can also be written as 3/4

Also given

Total number of students: 140

We will use ratios to find the number of boys and girls in shool.

First of all, we have to calculate the sum of ratio which is: 3+4 = 7

Let b be the number of boys and g be the number of girls

Then

$b = \frac{Ratio\ of\ boys}{Sum\ of\ ratio} * Total\ students\\= \frac{3}{7} * 140\\= 3*20\\=60\\g = \frac{Ratio\ of\ girls}{Sum\ of\ ratio} * Total\ students\\g = \frac{4}{7}*140\\= 4*20\\=80$

Hence,

There are 60 boys and 80 girls in Franklin School.

3 0

2 years ago

9^a-5 = 12<br><br> pls answer

xenn [34]

Answer:

a=1.29 approx

Step-by-step explanation:

5 0

2 years ago

Someone please answer this and not one of those bot links answer it someone an actual person please answer it I’ll give you brai

Artemon [7]

Answer:

1) y = 13.5x + 1
2) y = 12x + 4
3) Sam won the race

Step-by-step explanation:

Sam's car is 1 ft in front of the start line and its speed is 13.5 ft/s.

<u>The distance after x seconds is:</u>

y = 13.5x + 1

Alice's car the speed 12 ft/s and after 3 seconds is 40 ft in front of the start line.

<u>The distance after x seconds is:</u>

y = 12(x - 3) + 40 = 12x - 36 + 40 = 12x + 4

<u>After 15 seconds the distance from the start line is:</u>

Sam ⇒ y = 13.5*15 + 1 = 203.5 ft
Alice ⇒ y = 12*15 + 4 = 184 ft

As we see Sam is further from the start line than Alice

5 0

2 years ago

A cone and a triangular pyramid have a height of 9.3 m

Otrada [13]

Answer:

$x=17.1\ in$

Step-by-step explanation:

<u><em>The complete question is</em></u>

A cone and a triangular pyramid have a height of 9.3 m and their cross-sectional areas are equal at every level parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

$\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]$