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Simora [160]
3 years ago
8

PLEASE HELP, 46 PTS!!!! ANSWER QUICKLY AND WITH FULL REPONCE AND SHOW UR WORK!!

Mathematics
1 answer:
kramer3 years ago
5 0
Please limit your posts to one or two problems each.  Your demands ("show work," "answer quickly," "give a full response") should apply to YOU, not to people whom you hope will do your work for you.

<span>2. A pool company is trying out several new drains. Drain A empties a pool at a rate of 2 gal/min. Drain B empties a pool at a rate of 5 gal/min. One pool has 108 gal of water in it. Write an equation for each drain that shows the amount of time it takes to empty the pool. Then solve each equation showing your work.</span>

Drain A:  rate is 2 gal/min.  We do not know which pool has 108 gallons of water in it.  If it's Pool A, then the time required to empty Pool A is

108 gallons  
------------------- = 54 minutes
2 gallons/min 

If it's Pool B, then we can represent the amount of water in Pool B by b.  Then the time required to empty Pool B is 

   b (gallons)
------------------ = (b/5) minutes
5 gallons/min
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Compare and contrast the absolute value of a real number to that of a complex number.
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The equation V equals pi r squared h, where r represents radius and h represents height, is used to find the volume of a _______
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Answer:

Volume of a cylinder.

Step-by-step explanation:

The given equation is :

V=\pi r^2 h

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r is the radius

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This equation is used to find the volume of a cylinder.

For example, a cylinder having radius of 7 units and height of 10 units, its volume will be :

V=\dfrac{22}{7}\times 7^2\times 10\\\\V=1540\ \text{unit}^2

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Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x
Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

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(x-h)^2+(y-k)^2=r^2

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121

Make two groups for variable "x" and variable "y":

(x^2+10x)+(y^2-20y)=-121

Complete the square:

Add (\frac{10}{2})^2=5^2 inside the parentheses of "x".

Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

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You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

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3 years ago
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