Answer:
T1 = 975 / (205 + V) flying with wind
T2 = 975 / (205 - V) flying against wind
T2 = T1 + 2
975 * {1 / (205 - V) - 1 / (205 + V)] = 2
(205 + V + V -205) / (205^2 - V^2) = 2 / 975
V^2 + 975 V - 42025 = 0 rearranging
V = 41.3
Values of flying are 246.3 and 163.7
Check:
T1 = 975 / 246.3 = 3.96 hrs
T2 = 975 / 163.7 = 5.96 hrs
Answer:
(6,13)
Step-by-step explanation:
Hope that helps
Answer:
f(x) = |x - 4| + 3
Step-by-step explanation:
Identify (from the graph) the coordinates of the vertex: (4, 3). That +4 tells us that the vertex of the basic function y = |x| has been translated 4 units to the right; that +3 tells us that the vertex has also been translated 3 units up. Consider y = |x-a| + b. Here, b = +3 and a=+4. Thus, the correct function is f(x) = |x - 4| + 3.
Answer:
19.74 inches
Step-by-step explanation:
Given as
Circumference of wheel = 62 inches
AS we know that Circumference (C) = 2×
×R
where R is Radius of circle
so, C = 2 × 3.14 × R
or, 62 = 2 × 3.14 × R
or 62 = 6.28 × R
so, Radius (R) = 
R = 9.872
Now Diameter = 2 × Radius
so, D = 2 × 9.872
Diameter = 19.74 inches Answer
Answer:
heterozygous (Aa) are 0.085 = or 8.54%
Step-by-step explanation:
The heterozygous individuals are carriers of the sickle cell trait. They have a genotype of Aa and are represented by the 2pq term
in the H-W equilibrium equations.
According to the question 0.2% of the population is affected with sickle cell anemia, thus q^2
= 0.2% = 0.002 in decimal. So, q =
sqr(q^2)
or sqr(0.002) =
0.04472
and p + q = 1, thus p = 1 – q = 1 – 0.04472 = 0.96
Thus, A allele has a frequency of 0.96 and the a allele has a frequency of 0.04472. Therefore, the
percentage of the population that is heterozygous (Aa) and are carriers is = 2pq = 2× 0.04472× 0.96 =0.085 = or 8.54%
