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3 years ago

Just some simple math fro points reward brainliest

Mathematics

1 answer:

Ierofanga [76]3 years ago

7 0

First one is a function and the second one is also a function !

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I need answer ASAP If f(x) = 2x+1 and g(x) = 3x-2 Find f[g(1)] =

Nadya [2.5K]

Answer:

f[g(1)] = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 2x + 1

g(x) = 3x - 2

Step 2: Find g(1)

Substitute in x: g(1) = 3(1) - 2
Multiply: g(1) = 3 - 2
Subtract: g(1) = 1

Step 3: Find f[g(1)]

Substitute in g(1): f[g(1)] = 2(1) + 1
Multiply: f[g(1)] = 2 + 1
Add: f[g(1)] = 3

7 0

3 years ago

Convert 45.1% to a decimal.

Dafna11 [192]

Answer:

Queen Messy here!

0.451

moving the decimals to the left when dividing (:

Step-by-step explanation:

4 0

3 years ago

If quadrilateral ABCD is an isosceles trapezoid, which statements must be true? Check all that apply.

Helga [31]

Isosceles trapezoid has one pair of equal side and one pair of parallel side

For trapezoid ABCD, line AB equals to line CD and line AD is parallel to BC. The two diagonals, AC and BD, also has equal length.

Angle BAD equals to angle ADC
Angle ABC equals to BCD

Point E, where the two diagonals intersect, isn't the middle point of the diagonals.

Hence, from the options, the correct statements are
BC||AD
BA equals to CD
Angle CBA equals to angle BCD

5 0

3 years ago

Read 2 more answers

how do you rewrite : y=x^2-5x+9 in standard form using complying the square? I keep getting to : x^2-5x-25/4 but I’m not allowed

yawa3891 [41]

I presume with this you meant to say you want this equation in general form, also known as vertex form, which is y = a(x - h)² + k, instead of standard form, which is y = ax² + bx + c, which is what the original equation is already in.

So with completing the square, you first have to isolate the x-terms. To do this, subtract 9 on both sides of the equation:

$y-9=x^2-5x$

Next, we want to make the right side of the equation a perfect square. To find the constant of this soon-to-be perfect square, divide the x-coefficient by 2 and square that quotient. In this case:

$-5\div 2 = -\frac{5}{2}\\\\(-\frac{5}{2})^2=-\frac{5}{2}\times-\frac{5}{2}=\frac{25}{4}$

Now add 25/4 on both sides of the equation:

$y-9+\frac{25}{4}=x^2-5x+\frac{25}{4}$

Now to combine -9/1 and 25/4, they must have the same denominator, and to find it you must find the LCD, or lowest common denominator, of 1 and 4. To find it, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 4. Multiply both sides of -9/1 by 4/4 and then add the numerators up:

$-\frac{9}{1}\times \frac{4}{4}=-\frac{36}{4}\\\\-\frac{36}{4}+\frac{25}{4}=-\frac{11}{4}\\\\y-\frac{11}{4}=x^2-5x+\frac{25}{4}$