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AVprozaik [17]
3 years ago
12

Factor the expression completely -15t-6

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
5 0

Answer: -3(5t+2

Step-by-step explanation:

frozen [14]3 years ago
3 0

Answer:

−3(5t+2)

Step-by-step explanation:

lets factor out "3" from -15t-6

so factoring out "3" would give you -3(5t+2)

you can check ur work by distributing "3" hope this helps!

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The radius of an orange is 1.5 inches.
diamong [38]

Answer:

14.14

Step-by-step explanation:

V=4

3πr3=4

3·π·1.53≈14.13717

5 0
4 years ago
Write the slope intercept form of the equation of the line through the given points x intercept of -5 and y intercept of -1. Pls
soldier1979 [14.2K]

bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is  when the graph touches the y-axis and when that happens x = 0.

\bf \underset{x-intercept}{(\stackrel{x_1}{-5}~,~\stackrel{y_1}{0})}\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{-1}{0+5}\implies -\cfrac{1}{5}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1

4 0
3 years ago
Almeida collects data on the ages of the students in her aerobics class and creates a dot plot to represent the ages.
vazorg [7]
I believe your question is incomplete.
6 0
4 years ago
Read 2 more answers
This graph models the number of teachers assigned to a school, as determined by the number of students. What is the constant of
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(60,4)(120,8)
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8 0
3 years ago
Read 2 more answers
Are 12x^2y^3z and -45zy^3x2 like terms? explain why or why not.
Alex787 [66]

Here in the second term I am considering 2 as power of x .

So rewriting both the terms here:

First term: 12x²y³z

Second term: -45zy³x²

Let us now find out whether they are like terms or not.

"Like terms" are terms whose variables (and their exponents such as the 2 in x²) are the same.

In the given two terms let us find exponents of each variable and compare them for both terms.

z : first and second term both have exponent 1

x: first and second term both have exponent 2

y: first and second term both have exponent 3

Since we have all the exponents equal for both first and second terms variables, so we can say that the two terms are like terms.

4 0
3 years ago
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