Answer:
14.14
Step-by-step explanation:
V=4
3πr3=4
3·π·1.53≈14.13717
bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is when the graph touches the y-axis and when that happens x = 0.

![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B0%7D%3D%5Cstackrel%7Bm%7D%7B-%5Ccfrac%7B1%7D%7B5%7D%7D%5Bx-%5Cstackrel%7Bx_1%7D%7B%28-5%29%7D%5D%20%5C%5C%5C%5C%5C%5C%20y%3D-%5Ccfrac%7B1%7D%7B5%7D%28x%2B5%29%5Cimplies%20y%20%3D%20-%5Ccfrac%7B1%7D%7B5%7Dx-1)
(60,4)(120,8)
slope = (8 - 4) / (120 - 60) = 4/60 = 1/15 <== the constant of proportionality is the slope
Here in the second term I am considering 2 as power of x .
So rewriting both the terms here:
First term: 12x²y³z
Second term: -45zy³x²
Let us now find out whether they are like terms or not.
"Like terms" are terms whose variables (and their exponents such as the 2 in x²) are the same.
In the given two terms let us find exponents of each variable and compare them for both terms.
z : first and second term both have exponent 1
x: first and second term both have exponent 2
y: first and second term both have exponent 3
Since we have all the exponents equal for both first and second terms variables, so we can say that the two terms are like terms.