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2 years ago

Louis spent 12 hours practicing guitar if 1/4 of the time was spent practicing chords, how much time did Louis spend practicing

chords?

Mathematics

1 answer:

Kryger [21]2 years ago

8 0

$\frac{1}{4} \ of \ 12= \frac{1}{4}*12= \boxed{3 \ hours \ were \ used \ to \ chords}$

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At an end of the year sale, Gabriela bought more than 12 bottles of hand soaps and lotions. If x represents the number of hand s

nadya68 [22]

Answer:

the answer is b

Step-by-step explanation:

edge 2021

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3 years ago

Read 2 more answers

Need help on the 2 questions ASAP and SHOW WORK PLEASE !!!! 50 points ????

zaharov [31]

Answer:

-4 - 8-=-4

Step-by-step explanation:

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2 years ago

In the book Business Research Methods, Donald R. Cooper and C. William Emory (1995) discuss a manager who wishes to compare the

S_A_V [24]

Answer:

Null hypothesis is: U1 - U2 ≤ 0

Alternative hypothesis is U1 - U2 > 0

Step-by-step explanation:

The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.

Let U1 = mean sales by type A trainees

Let U2 = mean sales by type B trainees

Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0

This implies that type A training does not result in higher mean weekly sales than type B training.

The alternative hypothesis (H1) is: U1 - U2 > 0

This implies that type A training indeed results in higher mean weekly sales than type B training.

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2 years ago

The domain of the function f(x) = 3x3 is {2, 5}. What is the function’s range?

Sholpan [36]

The domain is {2,5} which the set containing the numbers 2 and 5. I'm assuming that the function is f(x) = 3x3<span>. So...

</span>when x = 2, f(x) = 3*23<span> = 3*8 = 24.
</span>when x = 5, f(x) = 3*53<span> = 3*125 = 375.

so this means the functions range is {24, 375}

hope this helped you out</span>

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2 years ago

HELP ASAP Calculate the residuals for your scatterplot in step 2d.

postnew [5]

The residuals of the linear regression equation are -1.36, 0.32, 0.01, 0.62, 0.17, -0.24, 0.89, 0.09, 0.18 and -0.7

<h3>How to determine the residuals?</h3>

The regression equation is given as:

y = 0.141x + 0.842

Next, we calculate the predicted values (y) at the corresponding x values.

So, we have:

y = 0.141 * 13.8 + 0.842 = 2.78

y = 0.141 * 18 + 0.842 = 3.38

y = 0.141 * 16.7 + 0.842 = 3.20

y = 0.141 * 18 + 0.842 = 3.38

y = 0.141 * 0.7 + 0.842 = 0.94

y = 0.141 * 21.9 + 0.842 = 3.93

y = 0.141 * 15.5 + 0.842 = 3.03

y = 0.141 * 9.2 + 0.842 = 2.14

y = 0.141 * 19.5 + 0.842 = 3.59

y = 0.141 * 16.7 + 0.842 = 3.20

The residuals are then calculated using:

Residual = Actual value - Predicted value

So, we have:

Residual = 1.42 - 2.78 = -1.36

Residual = 3.7 - 3.38 = 0.32

Residual = 3.21 - 3.20 = 0.01

Residual = 4 - 3.38 = 0.62

Residual = 1.11 - 0.94 = 0.17

Residual = 3.69 - 3.93 = -0.24

Residual = 3.92 - 3.03 = 0.89

Residual = 2.23 - 2.14 = 0.09

Residual = 3.77 - 3.59 = 0.18

Residual = 2.5 - 3.20 = -0.7

Hence, the residuals of the linear regression equation are -1.36, 0.32, 0.01, 0.62, 0.17, -0.24, 0.89, 0.09, 0.18 and -0.7