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Alex
3 years ago
7

98 POINTS ASAP

Mathematics
1 answer:
Temka [501]3 years ago
3 0

The rational root test leads to two roots of f(x), f(-1)=f(-2)=0, which means both x+1 and x+2 are factors.

\dfrac{x^4 -3x^3 - 5x^2 + 21x + 22}{(x+1)(x+2)}=x^2-6x+11

The discriminant of the remaining quadratic is negative ((-6)^2-4(11)=-8) and so it has no real roots. So

f(x)=(x+1)(x+2)(x^2-6x+11)

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fenix001 [56]

Answer:

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Answer:

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2 years ago
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aliina [53]
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Read 2 more answers
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Answer:

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