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3 years ago

Please I need help on this question

Mathematics

1 answer:

bulgar [2K]3 years ago

8 0

This should be a (2 and 3 only) because the graph never hits the x-axis so this rules 1 out. All of the other options have 1 in them so they are all incorrect. To check this we know the middle of the graph is x=2 making 3 true. 2 would be true because this is the point where the parabola hits the y axis.

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Why did colonists oppose the Stamp Act?How much would 3 go into 90

Nookie1986 [14]

Answer:

because it made them pay taxes on almost anything... it goes in 30 times....love yall

3 0

3 years ago

Read 2 more answers

Which of the following expressions is NOT equivalent to (x − 6)(x − 3)?

kodGreya [7K]

Answer:

B. x(x) + (−6)(−3)

NOT equivalent to (x − 6)(x − 3)

Step-by-step explanation:

(x − 6)(x − 3)

= x^2 - 3x - 6x + 18

= x^2 - 9x + 18

A. (6 − x)(3 − x)

= 18 - 6x - 3x + x^2

= 18 - 9x + x^2

= x^2 - 9x + 18 ---->equivalent to (x − 6)(x − 3)

B. x(x) + (−6)(−3) = x^2 + 18 ----> NOT equivalent to (x − 6)(x − 3)

C. x2 − 3x − 6x + 18 = x^2 - 9x + 18 --> equivalent to (x − 6)(x − 3)

D. x(x − 6) − 3(x − 6)

= x^2 - 6x - 3x + 18

= x^2 - 9x + 18 ---->equivalent to (x − 6)(x − 3)

4 0

3 years ago

Angelique makes beaded jewelry. The graph below shows the number of beads on varying cord lengths.

8_murik_8 [283]

Answer:

The Biden administration is extending a mask mandate for airplanes and transit for 15 days, the Centers for Disease Control and Prevention said Wednesday.

The mandate was set to expire after April 18, following a one-month extension announced in March. Airlines have required masks on planes since early in the pandemic in 2020, but the Biden administration made them mandatory in early 2021.

The CDC said it is monitoring the spread of omicron, including the BA.2 subvariant.

Step-by-step explanation:

23=4 3+4+7 1/2 4/7 8/2

6 0

2 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago

A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$

7 0

3 years ago