Question

f the probability of being hospitalized during a year is 0.25 ​, find the probability that no one in a family of five will be hospitalized in a year.

Answer 1

Answer:

The probability that no one in a family of five will be hospitalized in a year is 0,2373

Step-by-step explanation:

Let p denote the probability of being hospitalized during a year,

Then p=0.25

And p' the probability of not being hospitalized during a year is 1-p

Thus p' = 1-p = 1-0.25 = 0.75

The probability that no one in a family of five will be hospitalized in a year is equal to $p'^{5}$. That is

$p'^{5}$ = $0.75^{5}$ ≈ 0,2373