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kow [346]
3 years ago
11

Whale communication. Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard nea

rly 1000 km away in the ocean. What is the wavelength of such a sound in seawater, where the speed of sound is 1531 m/s?
Physics
1 answer:
Thepotemich [5.8K]3 years ago
6 0

Answer:

Wavelength, \lambda=90.05\ m

Explanation:

Given that,

Frequency of the sound wave, f = 17 Hz

It is heard 1000 km away in the ocean

The speed of sound is, v = 1531 m/s

Let \lambda is the wavelength of sound in seawater. We know that the relation between frequency and wavelength is given by :

v=f\times \lambda

\lambda=\dfrac{v}{f}

\lambda=\dfrac{1531\ m/s}{17\ Hz}

\lambda=90.05\ m

So, the wavelength of such a sound in seawater is 90.05 meters. Hence, this is the required solution.

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One kind of baseball pitching machine works by rotating a light and stiff rigid rod about a horizontal axis until the ball is mo
Veseljchak [2.6K]

Answer:

a. ac = 1844.66 m/s²

b. Fc = 265.63 N

Explanation:

a.

The centripetal acceleration of the ball is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = ?

v = speed of ball = (87 mph)(1 h/ 3600 s)(1609.34 m / 1 mile) = 38.9 m/s

r = radius of path = 82 cm = 0.82 m

Therefore,

ac = (38.9 m/s)²/0.82 m  

<u>ac = 1844.66 m/s²</u>

<u></u>

b.

The centripetal force is given as:

Fc = (m)(ac)

Fc = (0.144 kg)(1844.66 m/s²)

<u>Fc = 265.63 N</u>

6 0
3 years ago
Your microwave will not turn on, and you speculate that a circuit breaker in the house has been tripped. In scientific terminolo
Mars2501 [29]

Answer:

Your microwave will not turn on, and you speculate that a circuit breaker in the house has been tripped. In scientific terminology, the steps would be described as: <em><u>developing a hypothesis based on an observation</u></em>.

3 0
3 years ago
The motor of a ski boat generates an average power of 2.74 × 10^4 W when the boat is moving at a constant speed of 14.3 m/s. Whe
Roman55 [17]

Answer:

T = 4517.48 N

Explanation:

It is given that,

Average power of the motor, P_1=2.74\times 10^4\ W

Speed of the boat, v_1=14.3\ m/s

Force or tension acting on the motor at this point is given by :

P=T\times v

T=\dfrac{P_1}{v_1}

T=\dfrac{2.74\times 10^4}{14.3}

T = 1916.08 N

Average power generated by the engine, P_2=9.2\times 10^4\ W

Force or tension acting on the motor at this point is given by :

P=T\times v

T=\dfrac{P_2}{v_2}

T=\dfrac{9.2\times 10^4}{14.3}

T = 6433.56 N

So, the tension in the tow rope that is pulling the skier is, T = 6433.56 N - 1916.08 N = 4517.48 N

4 0
3 years ago
What is the equation used to calculate the total amount of energy used by an appliance?
charle [14.2K]

Answer:

Power = Current × Voltage

Explanation:

Units:

Power = Watts

Current = Àmperes

Voltage = Volts

8 0
3 years ago
A cart moves with negligible friction or air resistance along a roller coaster track. The cart starts from rest at the top of a
lina2011 [118]

Answer:

hinit = 17.5 m

Explanation:

  • Assuming no friction present, the mechanical energy must be conserved, which means that at any point of the trajectory, the sum of the gravitational potential energy and the kinetic energy must keep the same.
  • At the top of the hill, since it starts from rest, all the energy must be potential, and we can express it as follows:

       E_{o} = U_{o} = m*g*h_{init}  (1)

  • When the car arrives to the top of the second hill, as we know that it is lower than the first one, the energy of the car, must be part gravitational potential energy, and part kinetic energy.
  • We can express this final energy as follows:

       E_{f} = U_{f} + K_{f}  = m*g* h_{2} + \frac{1}{2} *m*v_{f} ^{2}  (2)

  • In order to find hinit, we need to make (1) equal to (2), and solve for it.
  • In (2) we have the value of h₂ (10 m), but we still need the value of the speed at the top of the second hill, vf.
  • Now, when the car is at the top of the hill, there are two forces acting on it, in opposite directions: the normal force (upward) and the weight (downward).
  • We know also that there is a force that keeps the car along the circular track, which is the centripetal force.
  • This force is just the net downward force acting on the car (it's vertical at the top), and is just the difference between the weight and the normal force.
  • If the cart just barely loses contact with the track at the top of the second hill, this means that at that point the normal force becomes zero.
  • So, the centripetal force must be equal to the weight.
  • The centripetal force can be expressed as follows:

       F_{c} = m*\frac{v_{f} ^{2}}{R}  (3)

  • We have just said that (3) must be equal to the weight:

       F_{c} = m*\frac{v_{f} ^{2}}{R} = m*g (4)

  • Simplifying, and rearranging, we can solve for vf², as follows:

       v_{f}^{2} = R*g  (5)  

  • Replacing (5) in (2), simplifying and rearranging in (1) and (2) we finally have:

      h_{init} = h_{2} + \frac{1}{2} R = 10m + 7.5 m = 17.5 m (6)

7 0
3 years ago
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