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Svetach [21]
3 years ago
12

Two identical 9.10-g metal spheres (small enough to be treated as particles) are hung from separate 300-mm strings attached to t

he same nail in a ceiling. Surplus electrons are added to each sphere, and then the spheres are brought in contact with each other and released. Their equilibrium position is such that each string makes a 13.0 ∘ angle with the vertical. How many surplus electrons are on each sphere?
Physics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

n = 1.266\times 10^{12}

Explanation:

Given data:

mass of sphere is 10 g

Angle between string and vertical axis is \theta = 13 degree

thickness of string  300 mm = 0.3 m

sin\theta =\frac{2}{0.3 m}

r =0.3 sin 13 = 0.067 m

Fe = \frac{ kq_1 q-2}{d^2}

Fe = \frac{kq^2}{(2r)^2} = mg tan\theta

q^2 =  mg tan\theta \frac{(2r)^2}{k}

    = 0.0091 \times 9.8 tan13 \times \frac{(2\times 0.067)^2}{9\times 10^9}

q^2 = 4.10\times 10^{-14}

q = 2.026 \times 10^{-7} C

q = ne

n = \frac{1.6\times 10^{-19}}{2.02\times 10^{-7}}

n = 1.266\times 10^{12}

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mariarad [96]

Answer:

Magnitude is 25.8 m/s and direction is 35.5^{o}

Explanation:

From the law of conservation of linear momentum

m_{b}v_{ib}+ m_{s}v_{is}= m_{b}v_{fb}+ m_{b}v_{fs} where m_{b} and m_{s} are masses of bullet and stones respectively, v_{ib} and v_{is} are the initial velocities of bullet and stone respectively, v_{fb} and v_{fs} are the final velocities of bullet and stone respectively

Substituting 6g=0.006 Kg for mass of bullet, 0.1Kg for mass of stone, 350 m/s for initial velocity of bullet and 250 m/s as final velocity for stone but initial velocity of stone is zero

0.006 Kg *350 m/s (\hat i)+0.1 Kg*0=0.006 Kg* 250 m/s (\hat j)+0.1*v_{fs}

2.1 Kg.m/s(\hat i)=1.5 Kg.m/s(\hat j)+ 0.1*v_{fs}

0.1*v_{fs}=2.1 Kg.m/s(\hat i)- 1.5 Kg.m/s(\hat j)

v_{fs}=21 Kg.m/s(\hat i)- 15 Kg.m/s(\hat j)

|v_{fs}|=\sqrt {(v_{x}^{2}+v_{y}^{2})}

Substituting 21 for v_{x} and 15 for v_{y}

|v_{fs}|=\sqrt {(21^{2}+15^{2})}=25.8 m/s

To find direction

tan\theta=\frac {v_{y}}{v_{x}}

\theta=tan^{-1}(\frac {15}{21})=35.5^{o}

Therefore, magnitude is 25.8 m/s and direction is 35.5^{o}

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4 years ago
Magnetic Field: is a region around the charged particle where the electric force is exerted on other charged particles.
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The answer for this question should be TRUE
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2 years ago
Ple can someone help me to answer this question
ra1l [238]

The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

<h3 /><h3>A sketch of the uniform stick and the mass</h3>

The sketch of the uniform stick and the mass will be two based on the given statement.

<h3>when the uniform stick balances on knife at 10 cm from one end;</h3>

-------------------------------------------------------  

↓      10cm           Δ       (L - 10 cm)         ↓

200g                                                      M

<h3>When the knife edge is moved 5 cm further</h3>

|---------------15 cm-----------------|

-----------------------------------------------------------------------

              ↓      8.75 cm           Δ       (L - 15 cm)         ↓

          200g                                                               M

From the first diagram, apply principle of moment;

200(10) = M(L - 10) ------- (1)

From the second diagram, apply principle of moment;

200(8.75) = M(L - 15)   ------- (2)

From equation (1); M = (2000) / (L - 10)

From equation (2); M = (1750) / (L - 15)

Solve (1) and (2);

(2000) / (L - 10) = (1750) / (L - 15)

1750(L - 10) = 2000(L - 15)

L - 10 = 2000/1750(L - 15)

L - 10 = 1.143(L - 15)

L - 10 = 1.143L - 17.14

17.14 - 10 = 1.143L - L

7.14 = 0.143L

L = 7.14/0.143

L = 50 cm

<h3>Mass of the uniform stick</h3>

M = (2000) / (50 - 10)

M = 50 g

Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

Learn more about length of meter stick here: brainly.com/question/17225736

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8 0
2 years ago
A doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the ot
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The patient apply pressure to his side of the tube is 15 x 10⁴ N/m². The correct option is D.

<h3>What is pressure?</h3>

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

Given is a doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the other side. The ball rises with a force of 150 N. The cross section are of the tube is 0.001 m³

The pressure applied is

p = 150 /0.001

p = 15 x 10⁴ N/m²

Hence, the patient apply pressure to his side of the tube is 15 x 10⁴ N/m².

Learn more about pressure.

brainly.com/question/12971272

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6 0
2 years ago
What is shown in the diagram? A). A turbine B). An electromagnet C). A motor D). A generator
AlexFokin [52]

Answer:

I just answered a question like this. It should be B. An electromagnet :)

Explanation:

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3 years ago
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