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bija089 [108]
3 years ago
7

-4p + 19 = 11 please help me due tomorrow

Mathematics
1 answer:
Valentin [98]3 years ago
6 0

Answer:

p=2

Step-by-step explanation:

−4p=11−19

−4p=−8

then you divide both sides by -4 and two negatives make a positive.

​​

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The answer will be 6(3)-4-32
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For neighborhood parks of a given size, the equation yˆ=7.219x+2.033 models the number of children at a park, where x is the num
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I'm not 100% sure, but I believe the answer would be:
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How many days will it take for a sum of $4,000 to earn $80 interest if it is deposited in a bank paying ordinary simple interest
Maksim231197 [3]

Answer:

It will take 146 days to earn an interest of $80.

Step-by-step explanation:

The simple interest formula is:

I=\frac{P\times r\times t}{100}

It is provided that:

I = $80

P = $4,000

r = 5% p.a.

Compute the time required as follows:

I=\frac{P\times r\times t}{100}

t=\frac{I\times 100}{P\times r}

  =\frac{80\times 100}{4000\times 5}\\\\=0.4\ \years\\\\=0.4\times 365\ days\\\\=146\ days

Thus, it will take 146 days to earn an interest of $80.

4 0
3 years ago
Write the numbers 57,000,000,000 and 19,000 in scientific notation. Then show how to divide 57,000,000,000 by 19,000 using prope
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Answer:

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Step-by-step explanation:

8 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

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n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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