Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Answer: Asexual reproduction
Asexual reproduction is a mode of reproduction in which a single parent is involved to produce the offsprings. This occurs in simple organisms. This does not requires formation of gametes like sexual reproduction. The offsprings are identical to the parent organism. Here, mother colony of protists, volvox gives birth to daughter as only single parent is involved it is a asexual mode of reproduction.
