Sickle cell disease (sickle cell anemia) is a genetic, inherited disease affecting red blood cells, in which a child can be ill if both parents are transmitters, ie asymptomatic carriers of the gene for sickle cell disease. It is a hereditary autosomal recessive disease, that is, it affects girls as well as boys, and only manifests itself when one carries two genes of the disease. This disease is genetic and therefore not contagious.
*So, to be sick from sickle cell disease, the person has to have two sick alleles in the chromosome.
*To have the sickle-cell trait without getting sick, the person has to have only one sick allele.
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Complete question, Answer, and Explanation:
Due to technical problems, you will find the complete question, answer, and explanation in the attached files.
Here we can see that 7 phenotypes appeared in F2 generation, so the number of genes involved is 3 and alleles is 6. Contribution per allele = 4 cm Base contribution = 6 cm
Genotype of Harvey = aa bb cc Genotype of Erma = AA BB CC
Number of dominant alleles if length is
18 cm = 18-6 / 4 = 12 / 4 = 3.
F1 generation genotype = Aa Bb Cc This clarifies why the length is 18 cm, as there are three dominant alleles.
seven 1. It is likely that there are gene pairs in this cross. There are
categories of phenotypes. The genotypes of the parents would be combinations of alleles that would produce a 6 cm ( aabbcc ) tail and a 30 cm) tail, whereas the 18 cm offspring would have a genotype of AaBbcc.
learn more about phenotypes here: brainly.com/question/902712
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