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9966 [12]
3 years ago
6

Two investments totaling $21,000 produce an annual income of $870. One investment yields 4% per year, while the other yields 10%

per year. How much is invested at each rate?
Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0

Answer:

The amount invested at 4% is $20,500 and the amount invested at 10% is $500

Step-by-step explanation:

Let

x -----> the amount invested at 4%

(21,000 -x) ----> the amount invested at 10%

we know that

The interest of the amount invested at 4% plus the interest of the amount invested at 10% must be equal to $870

4\%=4/100=0.04

10\%=10/100=0.10

so

0.04(x)+0.10(21,000-x)=870

Solve for x

0.04x+2,100-0.10x=870

0.10x-0.04x=2,100-870

0.06x=1,230

x=\$20,500

21,000-x=\$500

therefore

The amount invested at 4% is $20,500 and the amount invested at 10% is $500

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