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algol13
3 years ago
8

A prism has total surface area of 360 m2 and volume of 60 m². If the length, width,

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

480

Step-by-step explanation:

I did the test and this is what it said in the review.

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What is translation with 5 units right and 1 up
Leviafan [203]
Since you did not provide the coordinates, I can't provide an exact answer. 
However, I can tell you this; from the initial x-coordinate, move right 5 units. from the initial-y coordinate, move up 1 unit and you will have your answer. 
4 0
3 years ago
What is the value of x?<br> Please help fast will give brainliest help fast
serious [3.7K]

Answer:

17

Step-by-step explanation:

because of the kind of angle it is, the two equations are equal. So, put the equations equal to each other and solve:

x+35=3x+1

combine like terms (by subtracting)

2x=34

isolate x by dividing by 2

x=17

17

8 0
3 years ago
Read 2 more answers
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Yeah can someone help me plz
erastovalidia [21]
11. you do 3x3=9 then plus 9+2 = 12 then 12 x 12 = 144
sorry idk 10.
3 0
3 years ago
2,236.8 to the nearest ten
german

Answer:

Already rounded to the nearest tenth.

2236.8

Step-by-step explanation: k

6 0
3 years ago
Read 2 more answers
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