Let
x,y, and z the long sides of the triangle
we know that
x+y+z=170 ft------> equation 1
x/y=25/14----> y=14x/25------> equation 2
y/z=14/12-----> equation 3
x/z=25/12----> z=12x/25------> equation 4
substitute equation 2 and equation 4 in equation 1
x+[14x/25]+[12x/25]=170------> multiply by 25 both sides
25x+14x+12x=4250
51x=4250
x=4250/51
x=250/3
y=14x/25------> y=(250/3)*(14/25)----> y=140/3
z=12y/14-----> (140/3)*12/14----> z=40
Using Heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
where s is the semiperimeter
s=170/2-----> s=85 ft
Area=√85*[85-250/3]*[85-140/3]*[85-40]
Area=9.22*[1.67]*[38.33]*[45]------> Area=26558.21 ft²
the answer is
26558.21 ft²
The maximum area is when the rectangle is a square. The side of the square is 348/4=87ft.
The area is 87²=7569 sq ft.
-27. Divide 2 by 3, then -18 by that number to get -27.
We can plug in the values of this point to find b
-4 = 17 (3) +b
We will multiply 17 times 3
-4 = 51 + b
We then subtract by 51 on both sides
-55 = b
So the full equation will be
y = 17x - 55
