This makes a right triangle with hypotenuse x+2 and legs 10 and x
10²+x²=(x+2)²
100 + x² = x²+4x+4
100=4x+4
4x=96
x=24, the height we are looking for
48-2x=96--------- -2x=48--------- x=-24. You multiply everything by 6 then solve.
Answer:
y = 4(x+6)(x-2)
Step-by-step explanation:
y = 4x² + 16x - 48, factor out the 4
y = 4(x² + 4x - 12), find factors of 12
Factors of 12:
1*12, 2*6, 3*4; find a pair that sums to 4x or 4
6-2 = 4, since 12 is a negative number, a number in the factor must be negative, in this case, making 2 negative, would make 6-2 = 4
y = 4(x+6)(x-2)
X= 2/3
6x/x-6 - 4/x - 24 / x^2 - 6x = 0
6x^2 -4 (x-6)-24 / x(x-6) = 0
6x^2 -4x+ 24 -24/x(x-6) = 0
X(6x-4) / x(x-6)
6x-4/x-5 = 0
6x-4= 0
6x = 4 divide both sides by 6
X= 2/3