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joja [24]
3 years ago
9

A line intersects the point (3,-4) and has a slope of 17. What is the slope-intercept equation for this line? y = 17x + [?]​

Mathematics
2 answers:
solong [7]3 years ago
6 0
The full equation would be y = 17x - 55
Ilya [14]3 years ago
5 0
We can plug in the values of this point to find b
-4 = 17 (3) +b
We will multiply 17 times 3
-4 = 51 + b
We then subtract by 51 on both sides
-55 = b
So the full equation will be
y = 17x - 55
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I need help with this question! thank u :)
cestrela7 [59]
Presumably d meanst distance and t means time.

When t = 1, d = 2.5
When t = 3, d = 4

d = mt + b
2.5 = m + b [t = 1]
4.0 = 3m + b [t = 2]
1.5 = 2m [subtract]
m = .75 = slope
b = 1.75 = d-intercept
d = .75t + 1.75
d = 15/4 + 7/4 [t = 5]
d = 22/4 = 5.5 m from sensor
6 0
3 years ago
If the angles 2xº and 4yº<br> are<br> complementary, find the value of x + 2y.
ivolga24 [154]

Answer:

Solution given:

the angles 2xº and 4yºare complementary

so

2x+4y=90°

dividing both side by 2we get

x+2y=45°

<u>the value of x + 2y</u><u> </u><u>i</u><u>s</u><u> </u><u>4</u><u>5</u><u>°</u><u>.</u>

3 0
3 years ago
If f(x) -V7-3, complete the following statement (round your answer
nikklg [1K]

Answer:

- 1.67

Step-by-step explanation:

f(x) = \frac{3}{7+2} - \sqrt{7-3}

    =  \frac{3}{9} - \sqrt{4}

    = \frac{1}{3} - 2

    = - 1 \frac{2}{3}

    = -1.6666666

    = -1.67

5 0
3 years ago
The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin
anzhelika [568]

Answer:

Length=17.5\ in\\\\Width=11.5\ in

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

A=lw

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

P=2l+2w

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

A=201.25\ in^2\\\\P=58\ in

<u>The steps are:</u>

1. Solve for the "l" from the formula A=lw:

A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}

2. Substitute l=\frac{201.25}{w} into the formula P=2l+2w and solve for "w":

58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0

Applying the Quadratic formula x=\frac{-b\±\sqrt{b^2-4ac}}{2a}, we get:

x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5

3.  Substitute w_1=17.5 into l=\frac{201.25}{w}:

l=\frac{201.25}{17.5}=11.5

4. Substitute w_2=11.5 into l=\frac{201.25}{w}:

l=\frac{201.25}{11.5}=17.5

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

l=17.5\ in\\\\w=11.5\ in

8 0
3 years ago
Plz help me well mark brainliest If Correct
Masja [62]
You would have to begin at (2,4) to reach (5,6)
6 0
3 years ago
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