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konstantin123 [22]
3 years ago
11

A pair of single quotes ( ‘ ) will prevent the shell from interpreting any metacharacter.

Computers and Technology
1 answer:
rusak2 [61]3 years ago
7 0

Answer: True

Explanation:

In Linux, a single quote around a string will prevent the shell from interpreting any metacharacter.

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Prominent is another word for stands out. True False
earnstyle [38]
The answer is TRUE.

There you go.
6 0
3 years ago
The true or false questions.
tankabanditka [31]

Answer:

false

Explanation:

-exec option is not mandatory for the find command.

find will still list out the identified files even in the absence of -exec option.

For example:

find . -name test -print

will print out files with the name 'test' in the current directory. Note that there is no exec option in this example.

Same holds true for find with no additional options at all.

For example:

find .

will list out all files in the current directory.

3 0
3 years ago
Write the following arithmetic expression as a valid C arithmetic expression: x = x + number
otez555 [7]

Answer:

x = x + number

x+=number

Explanation:

Given

x = x + number

Required

Write an equivalent expression in C

The given expression uses + and + is represented as + in C

So: The equivalent expression is

x = x + number

However, C supports compound assignment operators

So:

x = x + number

can be rewritten as

x+=number

3 0
3 years ago
Please help!!!
Alchen [17]

The most probable reason why your code for the dog turning right instead of is because your conditional statements are not satisfied.

<h3>What is Debugging?</h3>

This refers to the identification and removal of errors in a given code or hardware component.

Hence, we can see that you should note that you are using teh ifElse conditional statement to execute your code and you stated that the dog would turn right if:

  1. The left side is blocked
  2. If there are balls present.

Therefore, there are balls present and also the left side is blocked which causes your dog to turn right because it is executing the else statement.

Read more about debugging here:

brainly.com/question/16813327

#SPJ1

6 0
2 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "To
Ludmilka [50]

Answer:

#include <iostream>

using namespace std;

void PrintPopcornTime (int bagOunces){

   if (bagOunces < 2){

       cout << "Too small"<<endl;

   }

   else if (bagOunces > 10){

       cout << "Too large"<<endl;

   }

   else{

       cout << bagOunces*6 <<" seconds"<<endl;

   }

}

int main(){

   PrintPopcornTime(7);

   

   return 0;

}

Explanation:

Create a function called PrintPopcornTime that takes one parameter, bagOunces

Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".

Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.

4 0
3 years ago
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