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GREYUIT [131]
3 years ago
7

Raul wants to buy a new collar for each of his 3 cats. The collars come in a choice of 4 different colors. Step 2 of 2 : How man

y selections of collars are possible if repetitions of colors are not allowed
Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Answer:

si

Step-by-step explanation:

Anni [7]3 years ago
7 0

Answer:

24

Step-by-step explanation:

4C1×3C1×2C1

=4×3×2

= 24

One option less than before because colours can not be repeated

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PLEASE HELP!!
Alborosie

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A sample of baseball games shows that the mean length of the games is 179.83 minutes. (The data is given in BaseballTimes if you
Dmitriy789 [7]

Answer: Yes, This sample provide evidence that the length of time for baseball games is more than 170 minutes.

Step-by-step explanation:

Since we have given that

Mean length of the games = 179.83

Standard error = 3.75

We need to find the value of P(X>170).

So, it becomes,

z=\dfrac{X-\mu}{s}=\dfrac{179-170}{3.75}\\\\z=2.4

Let z_{crict}=1.64

Since z is greater than z(critical value).

So,Yes, This sample provide evidence that the length of time for baseball games is more than 170 minutes.

5 0
3 years ago
Two hundred raffle tickets are sold for $3 each. One prize of $500 is to be awarded. Winners do not have their ticket coat refun
Nady [450]
You should rewrite this question
5 0
3 years ago
A high school is having a pancake breakfast fundraiser.They have 5 packages of pancake mix that each feed 140 people.The functio
Charra [1.4K]

Answer:

They have 5 packages of pancake mix.

N(p) = 140*p

Represents the number of people that can be feed with p = # of packages of pancake mix used.

Now, the domain will be the set of the possible values of p that we can use here.

the set of possible values of p will be:

{0, 1, 2, 3, 4, 5}

We can not use more than 5 because there are only 5 packages.

But we can use actually half a package or a third, so we not should use only whole numbers in the domain, then the domain can be written as:

D = 0 ≤ p ≤ 5

Now, the range is the set of the possible values of N(p)

The minimum will be when p = 0.

N(0) = 140*0 = 0

The maximum will be when p = 5

N(5) = 140*5 = 700

Then the range can be written as:

R = 0 ≤ N ≤ 700

Here we could add another restriction, because we can only feed a whole number of people, then we also should add the restriction that N must be a whole number:

R = 0 ≤ N ≤ 700, N ∈ Z

3 0
3 years ago
Circle
Doss [256]
Siras !  Don't try to picture this all in your head !
You'll wear out your brain.
You MUST sketch it on a piece of paper.
Draw an x-axis and a y-axis, then draw the two circles.

I'm drawing myself a picture right now, and I'm
supposed to be some kind of a genius.

a).  In order to move Circle-Q so that both centers are
at the same point, you need to move the center of Q
4 units down and 2 units to the right.
      When you do that, you'll have the little circle inside the
big circle, with their centers both at the same place.

b).  The radius of Q is 2.
       The radius of P is 20.
       What do you have to multiply 2 by, in order to get 20 ?
       THAT's the scale factor to dilate Q so that it has the same
radius as P.
       When you do that, suddenly it'll look like you only have one circle
on the paper ... they'll both have the same radius and their centers are
at the same place, so you can't tell them apart.

c).  All circles are similar !

I went online (you could easily go there too).  I searched the question
"Are circles similar ?" and a lot of interesting stuff came up.  (you could
do that too).  I saw a lot of ways to prove that all circles are similar. 
The best one says:

       Two figures are "similar" if you can make one of them
       exactly fit on top of the other one (make them congruent)
       with translations and dilations.

You just did that with P and Q !

-- Translation is moving them around.
   You moved Q and put the centers of both circles at the same place.

-- Dilation is blowing it up or blowing it down, so its size changes
but its shape doesn't change.
   You blew Q up so that it had the same radius as P.
   Then the two circles exactly fit over/under each other.

So the two circles are similar. 
8 0
3 years ago
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