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GREYUIT [131]
2 years ago
7

Raul wants to buy a new collar for each of his 3 cats. The collars come in a choice of 4 different colors. Step 2 of 2 : How man

y selections of collars are possible if repetitions of colors are not allowed
Mathematics
2 answers:
jeka57 [31]2 years ago
8 0

Answer:

si

Step-by-step explanation:

Anni [7]2 years ago
7 0

Answer:

24

Step-by-step explanation:

4C1×3C1×2C1

=4×3×2

= 24

One option less than before because colours can not be repeated

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Sixty miles per hour is the same rate as<br> which of the following?
Genrish500 [490]

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C.  1 mile per minute.

Step-by-step explanation:

By proportion, 60 miles per hour = 1 mile per 1/60 of an hour.

1/60 hour = 1 minute.

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3 years ago
Find the area of the triangle ​
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I think it's 36 from top to bottom

Step-by-step explanation:

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1 year ago
What is -7 to the second power
Paha777 [63]

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34 divided by 3 3/4 equals what in fraction form
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2 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
2 years ago
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