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QN = 28
Solution:
Given MNPQ is a parallelogram.
QT = 4x + 6 and TN = 5x + 4
To find the length of QN:
Let us solve it using the property of parallelogram.
Property of Parallelogram:
Diagonals of the parallelogram bisect each other.
Therefore, QT = TN
⇒ 4x + 6 = 5x + 4
Arrange like terms together.
⇒ 6 – 4 = 5x – 4x
⇒ 2 = x
⇒ x = 2
Substitute x = 2 in QT and TN
QT = 4(2) + 6 = 14
TN = 5(2) + 4 = 14
QN = QT + TN
= 14 + 14
QN = 28
The length of QN is 28.
Answer:
y= f(x)-5
Step-by-step explanation:
y=f(x) moves 5 to the right
Answer:
27 days
Step-by-step explanation:
It is a simple division question
18 / (2/3)
Multiply by reciprocal
18 * 3 / 2 = 27
Answer:
The length of one leg of the triangle is 22 units
Step-by-step explanation:
The complete question in the attached figure
Let
x ----> the length of one leg of the triangle
we know that
In the right isosceles triangle of the figure
The cosine of angle of 45 degrees is equal to the adjacent side to angle of 45 degrees divided by the hypotenuse
---> equation A
----> equation B
equate equation A and equation B and solve for x


therefore
The length of one leg of the triangle is 22 units