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qwelly [4]
3 years ago
13

Which is greater 3.95, 3 5/6, 3 4/5

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0
The answer to your question is 3.95, if u divide 5/6 u get 83%, if u then divide 4/5 you get 80%
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Step-by-step explanation:

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2 years ago
Can someone explain this for me??<br> 4 (c+2) &lt; 4c + 10
faust18 [17]

Answer:

The inequality would be true

Step-by-step explanation:

4(c+2) < 4c + 10

Distribute the 4 on the left

4c + 8 < 4c + 10

Subtract 4c from both sides

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7 0
3 years ago
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
Fill in the blank.
Marrrta [24]

Question:

Fill in the blank.

23 x 6 = (20 + 3) * 6

23 x 6 = _ + (3x6)

Options

20 * 6

20 * 3

20 * 5

Answer:

20 * 6

Step-by-step explanation:

Given

Expression 1:  23 * 6 = (20 + 3) * 6

Expression 2:  23 * 6 = __ + (3 * 6)

Required

Fill in the blank

From Expression 1

23 * 6 = (20 + 3)*6

Using Distributive Property; The expression becomes

23 * 6 = 20 * 6 + 3 * 6

23 * 6 = (20 * 6) + (3 * 6)

By Comparing this with expression 2

23 * 6 = __ + (3 * 6)

The blank position is occupied by 20 * 6.

Hence, the correct option that fills the missing blank correctly is 20 * 6

7 0
2 years ago
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