I think it’s the second one but i am not 100% sure
P(most favorable outcome) = 1 -(0.03 +0.16 -0.01) = 0.82
_____
"repair fails" includes the "infection and failure" case, as does "infection". By adding the probability of "repair fails" and "infection", we count the "infection and failure" case twice. So, we have to subtract the probability of "infection and failure" from the sum of "repaire fails" and "infection" in order to count each bad outcome only once.
The probability of a good outcome is the complement of the probability of a bad outcome.
Answer:
0
Step-by-step explanation:
pretty easy tbh
Answer:
W = 76m
L = 83
Step-by-step explanation:
Answer: first would be 6 the next would be 12 then the next would be 18 and so on just add 6 for each one and for ten pizzas it would be 6*10 and that equals 60 im sure you get it
