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aliina [53]
3 years ago
12

Hannah reads 3 pages every 8 minutes.

Mathematics
2 answers:
azamat3 years ago
6 0

Number of pages read by Hannah in 8 minute = 3 pages

Number of pages read by Hannah in a minute = \frac{3}{8} Pages --(1)

If number of pages read by Hannah = p Pages

and , Number of minutes = m Minutes

m Minutes = p Pages

1 Minutes = \frac{p}{m} Pages --------(2)

Equating (1) and (2), we get

\frac{p}{m}=\frac{3}{8}\\\\8 p = 3 m

This is a linear relationship in number of pages read by Hannah and number of minutes Hannah spends reading.

PilotLPTM [1.2K]3 years ago
3 0
P = 3/8m, In other words, The number of pages she reads is equal to 3/8 times the number of minutes that she is reading for. We divide 3 by 8 to find out how many pages she reads per minute, which we can then times by how many minutes she is reading for to work out the total number of pages she has read. Hope this helps!
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What quadrilateral have all the attributes of rhombus ​
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3 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
Read 2 more answers
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