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VLD [36.1K]
3 years ago
14

Evaluate 4 E (2n-1) n=1

Mathematics
1 answer:
miv72 [106K]3 years ago
4 0

16

the simplest way to evaluate is to substitute n = 1, 2, 3, 4 into the expression and sum the terms

= [(2 × 1) - 1 ] + [(2 × 2) - 1 ] + [(2 × 3) - 1] + [(2 × 4) - 1]

= 1 + 3 + 5 + 7 = 16


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