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larisa [96]
3 years ago
9

I need help big time! Thanks for anyone who can answer this question!

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

51÷2=25.5 31÷2=15.5. 25.5× 15.5= 395.25

you just have to multiply

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Woody and Jen were paid $60 to paint the garage. Jim started at 8 a.M. And Woody didn't arrive until 10 a.M. The work was comple
Dennis_Churaev [7]

Answer:

$36

Step-by-step explanation:

Jim worked from 8am - 2 pm , which is 6 hours

Woody worked form 10am - 2pm, which is 4 hours

If we take the total time (4+6 = 10) and divide the amount they got, we have:

$60/10 = $6 per hour worked

Since Jim worked 6 hours, he will be paid 6 * 6 = $36

The rest, 60 - 36 = $24 would be paid to Woody (he worked less).

Jim's fair share of earning is $36

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To solve for y in the equation 2 x + y = 5, subtract 2 from both sides of the equation.
steposvetlana [31]

Answer:

False.

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Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
2 years ago
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