Answer:
Area of the remaining triangle with the villager is 1243.13 m²
Step-by-step explanation:
Triangle ABC is the triangular plot of a villager shown in the figure attached.
Sarpanch requested the villager to donate land which is 6 m wide and along the side AC which measures 132.8m.
Other sides of the plot has been given as AB = 50m and BC = 123 m.
Now area of this land before donation = 
= 
= 3075 square meter
After donation of the land the triangle formed is ΔDBE.
In ΔABC,

tan(∠ABC) = 
= 0.4065
∠ABC = 
= 22.12°
In ΔEFC,
tanC = 
0.4065 = 
CF = 
CF = 14.76 m
Since DE = AC - (CF + AG)
= 132.8 - (2×14.76)
= 132.8 - 29.52
= 102.48 m
Now in ΔDBE,
sin(∠DEB) = 
sin(22.12) = 
DB = 102.48×0.3765
= 38.59 m
Similarly, cos(22.12) = 
0.9264 = 
BE = 102.48×0.9264
= 94.94m
Now area of ΔDBE = 
= 
= 1831.87 square meter
Area of remaining triangle with the villager = Area of ΔABC - Area of ΔDBE
= 3075 - 1831.87
= 1243.13 square meter
Answer:
Area = 
Step-by-step explanation:
<u>The Complete Question:</u>
A rectangle has height
and width
. What is the area of the rectangle in terms of x?
<u>Solution:</u>
The formula for the area of a rectangle is:
Area = Height * Width
Both the expressions for height and width is given, so we just need to multiply both the expressions to get an expression, in x, for the area of the rectangle. The algebra is shown below:

This is the area of the rectangle.
Answer:
4x + 6
Step-by-step explanation:
If i remember correctly, two minuses make a positive, so -(-6) would turn into +6. I dont think that you can add a number with a variable to a regualar number so the answer is as simplified as it can get. If that one is wrong, try 10x. Hope this helps!
Answer: the product is = 33+4i
Step-by-step explanation:
21+4i-12i^2
21+4i-12(-1) i^2=-1
21+4i+12
your answer would be 33+4i .
Answer:

Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The figure shows a kite
The kite has two pairs of consecutive and congruent sides and the diagonals are perpendicular
That means
TS=VS
TQ=VQ
TR=RV
we have


so

solve for x

<em>Find the value of RV</em>

substitute the value of x

Remember that
---> by segment addition postulate
we have

so
