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VLD [36.1K]
3 years ago
7

Draw the straight line y= x+2

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

Attached below

Step-by-step explanation:

Hope this helped

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Find the solution to the system of equations. 4x + 3y = –1 3x – 9y = 33 solution = ( , )
tensa zangetsu [6.8K]

Answer:

(x, y) =(2,-3)

Step-by-step explanation:

4x+3y=-1

3x-9y=33 /:3

4x+3y=-1.....(1)

x-3y=11... (2)

(1)+(2): 5x=10

x-3y=11

x=10/5

x-3y=11

x=2

2-3y=11

x=2

-3y=11-2

x=2

-3y=9

x=2

y=9/(-3)

x=2

y=-3

(x,y)=(2,-3)

8 0
3 years ago
Read 2 more answers
mr henderson mixed 3.732g of chemical A, 13.902 of chemical B and 5.208g of Chemical C to make 3 does of medicine, About how muc
Dafna11 [192]

Answer:

22.8 grams

Step-by-step explanation:

To find total amount of medicine, we have to add all the 3 quantities of Chemical A, Chemical B, and Chemical C.

Before we do that, we have to round up each quantity to the nearest tenths.

Nearest tenths means we can take "1 digit" after the decimal point. For that we use rounding rules.

If the 2nd digit to the right of decimal is 5 or greater, we round up the 1st digit to the next whole number. If the 2nd digit is less than 5, we keep the 1st digit same.

So, using that we round up each of the three numbers as shown:

3.732 becomes 3.7 (since 3 is less than 5, we keep the 7)

13.902 becomes 13.9 (since 0 is less than 5, we keep 9)

5.208 becomes 5.2 (since 0 is less than 5, we keep 2)

Now we add:

3.7 + 13.9 + 5.2 = 22.8 grams

6 0
3 years ago
Rationalize the numerator or denominator, and simplify:
allochka39001 [22]
\dfrac{\sqrt[3]{x+h}-\sqrt[3]x}h\times\dfrac{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}=\dfrac{(\sqrt[3]{x+h})^3-(\sqrt[3]x)^3}\cdots
=\dfrac{x+h-x}\cdots=\dfrac h\cdots

The hs then cancel, leaving you with the \cdots=\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2} term.

If it's not clear what I did above, consider the substitution a=\sqrt[3]{x+h} and b=\sqrt[3]x. Then

a^3-b^3=(a-b)(a^2+ab+b^2)
\implies\dfrac{a-b}h=\dfrac{a-b}h\times\dfrac{a^2+ab+b^2}{a^2+ab+b^2}=\dfrac{a^3-b^3}{h(a^2+ab+b^2)}
4 0
3 years ago
Choose a rule for the translation.​
pantera1 [17]
Your answer would be B, X+2 Y-1
3 0
3 years ago
Find the solution set <br><br>2x^2 -2x -4 =0<br><br>please use a comma to separate your answer.
mariarad [96]

Answer:

2,-1

Step-by-step explanation:

2x^2 -2x -4 =0

Factor out a 2

2(x^2 -x-2) =0

What 2 number multiply to -2 and add to -1

-2*1 = -2

-2 +1 = -1

2(x-2) (x+1) =0

Using the zero product property

x-2 = 0               x+1 = 0

x-2+2=0+2       x+1-1=0-1

x=2                   x=-1

7 0
3 years ago
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