Answer:
m∠A = 91°
m∠B = 146°
m∠C = 89°
m∠D = 34°
Step-by-step explanation:
- If the four vertices of a quadrilateral lie on the edge of a circle, then this quadrilateral is called cyclic quadrilateral
- In the cyclic quadrilateral each two opposite angles are supplementary (means the sum of their measures is 180°)
- The sum of the measures of the interior angles of any quadrilateral is 360°
In quadrilateral ABCD
∵ A, B, C, And D lie on the circumference of the circle
∴ ABCD is a cyclic quadrilateral
∴ The sum of the measures of each opposite angles is 180°
∵ ∠A and ∠C are opposite angle in the cyclic quadrilateral ABCD
∴ m∠A + m∠C = 180°
∵ m∠A = (2x + 3)°
∵ m∠C = (2x + 1)°
- Add them and equate the answer by 180
∴ (2x + 3) + (2x + 1) = 180
- Add the like terms in the left hand side
∴ 4x + 4 = 180
- Subtract 4 from both sides
∴ 4x = 176
- Divide both sides by 4
∴ x = 44
Substitute the value of x in the expressions of angle A, C, D
∵ m∠A = 2(44) + 3 = 88 + 3
∴ m∠A = 91°
∵ m∠C = 2(44) + 1 = 88 + 1
∴ m∠C = 89°
∵ m∠D = x - 10
∴ m∠D = 44 - 10
∴ m∠D = 34°
- ∠B and ∠D are opposite angles in the cyclic quadrilateral ABCD
∴ m∠B + m∠D = 180°
∴ m∠B + 34 = 180
- Subtract 34 from both sides
∴ m∠B = 146°
a quarter is 1.75 mm thick
1 mm = 0.0393701 inches
0.0393701/12 = 25.4 mm per inch
25.4/1.75 = 14.5 quarters per inch
14.5 x 12 = 174 quarters per foot
174 x 0.25 = 43.50
$43.50 for a foot of quarters
Answer:
B
Step-by-step explanation:
Since this right angled triangle has two angles of 45, so according to theorem sides opposite to equal angles are equal
Applying Pythagoras theorem
(4√2)^2=(x)^2+(x)^2
32=x^2+x^2
32=2x^2
x^2=32/2
x^2=16
Taking sq root on both sides we get
x=4
See the attached picture for solution:
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