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avanturin [10]
3 years ago
12

6x+3y=6 what does x equal

Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

x=1-.5y

Step-by-step explanation:

6x+3y=6

6x=6-3y

x=1-.5y

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Find the GCF (Greatest Common Factor) of 64 and 144
valkas [14]

Answer: 16

Step-by-step explanation:

if we were to list all the factors of 64 and 144

64= 1,2,4,8,8,16,32,64

144= 1,2,3,4,6,8,9,12,12,16,18,24,36,48,72,144

therefore the GCF of 64 and 144 is 16

3 0
4 years ago
Read 2 more answers
5w - 15 = 25 what is w
7nadin3 [17]
Solve for "w" by adding 15 to both sides of the equation.
5w-15=25
5w=40
Next, divide both sides by 5 to get "w" by itself.
5w=40
W=8
4 0
4 years ago
Read 2 more answers
What is the percent error in the meteorologists forecast for Monday?
cupoosta [38]

Answer:

The percent error in the meteorologist's forecast for Monday is 5.26316 %

Step-by-step explanation:

7 0
3 years ago
The ratio of 5 rupee notes to 10 rupee notes in a purse is 3 : 4. There are 77 notes in the purse. How much money is there in th
Norma-Jean [14]

Answer:

605 rupees

Step-by-step explanation:

add the parts of the ratio 3 + 4 = 7

divide the number of notes by 7 to find one part of the ratio

\frac{77}{7} = 11 ← 1 part of the ratio

3 parts = 3 × 11 = 33 ← number of 5 rupee notes

4 parts = 4 × 11 = 44 ← number of 10 rupee notes

Amount of money = (33 × 5 ) + (44 × 10) = 165 + 440 = 605 rupees



4 0
3 years ago
Eric ran from school to the town monument and back again. On his way to the monument, he ran at 10kph and went back to school at
Aloiza [94]

Answer:

Distance = 10 km

Step-by-step explanation:

Let x be the number of hours taken from school to town and y be the number of hours taken back to the school

Then distance covered during first trip would be 10x (distance = speed*time) and during the second trip would be 8y. Both distances are equal.

=> 10x = 8y  

Dividing both sides by 2

=> 5x = 4y

=> 5x-4y = 0   ------------------(1)

<u><em>The total time for both the trips is:</em></u>

=> x + y = 2.25 -------------------(2)

Multiplying eq (2) by 5

=> 5x+5y = 11.25  ---------------(3)

Subtacting (3) from (1)

=> 5x-4y-5x-5y = 0-11.25

=> -4y-5y = -11.25

=> -9y = -11.25

Dividing both sides by -9

=> y = 1.25 hrs

Putting in (2)

=> x + 1.25 = 2.25

=> x = 2.25 - 1.25

=> x = 1 hr

<u><em>Now, Calculating the Distance</em></u>

=> Distance = 10x

=> 10 ( 1 )

=> Distance = 10 km

3 0
4 years ago
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