Evaluate the expression below when x = -2. x2 − 8 x + 6

1 answer:

3 0

First, substitute -2 into each equation where there is an x:
(-2)2 -8
(-2) +6

Then multiply the -2 and the 2 in the first equation and add -2 and 6 in the second:
-4 -8
4

Lastly, subtract -4 and 8:
-12
4

Now you have you answers -12 and 4!

You might be interested in

Diane is participating in a 4-day cross-country biking challenge. She biked for 57, 67, and 45 miles on the first three days. Ho

ella [17]

Answer:

139

Step-by-step explanation:

57+67+45=169÷3=139

6 0

3 years ago

Convert 9 over 16 to a decimal. A. 0.4225 B. 0.5225 C. 0.5625 D. 0.7455

Brums [2.3K]

C. 0.5625...you find the answer by dividing 6 by 19 :)

7 0

3 years ago

Read 2 more answers

Need help ASAP Which number line correctly shows -3 - -1.5?

Alexandra [31]

Answer:

The top one I'm pretty sure.

3 0

3 years ago

Which two statements describe the end behavior of the function?

Rom4ik [11]

What function? What’s the full question

5 0

3 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$