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Ganezh [65]
2 years ago
6

An exponential function, f, passes through the points (-2,-4) and (1,10). Which two points would lie on the graph of function g

if g(x) = 3f(x)?
Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

Answer:

(-2,-12) and (1,30)

Step-by-step explanation:

we know that

f(x) passes through the points (-2,-4) and (1,10)

That means

For x=-2 ----> f(-2)=-4

For x=1 ----> f(1)=10

we have

g(x)=3f(x)

so

substitute the given value of f(x) to obtain the value of the function g(x)

For x=-2 -----> g(-2)=3f(-2) ----> g(-2)=3(-4)=-12

For x=1 -----> g(1)=3f(1) ----> g(1)=3(10)=30

therefore

The two points that would lie on the graph of function g are

(-2,-12) and (1,30)

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Pls help find the amount at the end of 6 hours
marshall27 [118]

Answer:

A. 7,348

Step-by-step explanation:

P = le^kt

intitial population = 500

time = 4 hrs

end population = 3,000

So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.

A = Pe^rt

3,000 = 500e^r4

now we can solve for r

divide both sides by 500

6 = e^r4

now because the variable is in the exponent, we have to use a log

log_{e}(6) = 4r

ln(6) = 4r

we can plug the log into a calculator to get

1.79 = 4r

divide both sides by 4

r = .448

now lets plug it back in

A = 500e^(.448)(6 hrs)

A = 7351.12

This is closest to answer A. 7,348

4 0
3 years ago
A rectangular prism has a length of 3/8 a width of 5/8 and height of 7/8, what is the volume
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3 years ago
What is the answer to |-5-3|-|12-8|=?
Rudiy27

Answer:

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Read 2 more answers
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\huge\text{Hey there!}

\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}

\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}

\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}

\large\text{Equation: }\mathsf{\dfrac{(2x)^2-3^2}{2x + 3}}

\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}

\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}

\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}

\large\text{This leaves us with }\mathsf{\bf 2x - 3}\large\text{ as your POSSIBLE  ANSWER}

\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}

3 0
3 years ago
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