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Oliga [24]
4 years ago
8

Atoms of which element react spontaneously with Mg2+(aq)?

Chemistry
2 answers:
Delvig [45]4 years ago
5 0
<span>The complete answer contains the answer choices.
</span><span>
</span><span>
</span><span>This is the complete question:
</span><span>
</span><span>
</span><span>Atoms of which element react spontaneously with Mg2+(aq)? </span><span /><span> (1)chromium
(2)barium
(3)iron
</span><span> (4)zinc
</span>

Answer: option 2. barium.

Explanation.

1) Mg ²⁺ (aq) is the aquous cation of the metal Mg.

2) Only a metal more reactive than Mg will be able to exchange with it the oxidation states.

3) Mg is an earth alkalyne metal (group 2 of the periodic table). The metals from this group are more reactive than the metals in the groups to its right: 3, 4, 5, 6, 7, ... Only the alkalyne metals (those in group 1) are more reactive than the earth alkalyne metals.

4) Of the list, barium is the only alkalyne metal, so it is more reactive than Mg and will be able to deliver 2 electrons to transform the cations Mg²⁺ into Mg while the very Ba will become Ba²⁺.

5) Chromium, iron and zinc are transition metals, so less metallic (reactive) than Mg.
<span />
jenyasd209 [6]4 years ago
4 0
Answer is: <span>(2) barium.

Chemical reaction: Mg</span>²⁺(aq) + Ba(s) → Mg(s) + Ba²⁺(aq).<span>
</span>

Reactivity series is an empirical progression of a series of metals, arranged by their reactivity from highest to lowest (alkaline metals have highest reactivity and Noble metals lowest reactivity). 

This series are used to summarize information about the reactions of metals with acids or water, double displacement reactions (more reactive metals displace metals with lower reactivity) and the extraction of metals from their ores.

In this example, barium is more reactive than magnesium, iron, chromium and zinc are less reactive.


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For the reaction: CO(g) + H2O(g) ⇌ CO2(g) + H2(g) the value of Kc is 1.845 at a specific temperature. We place 0.500mol CO and
patriot [66]

Answer:

Explanation:

In the equilibrium:

CO(g) + H₂O(g) ⇄ CO₂(g) + H₂(g)

Kc is:

Kc = 1.845 = [CO₂] [H₂] / [CO] [H₂O]

<em>Where [] are equilibrium concentrations of each species</em>

<em />

Initial concentrations:

[CO] = 0.500mol / 1.00L = 0.500M

[H₂O] = 0.500mol / 1.00L = 0.500M

In equilibrium, concentrations will be:

[CO] = 0.500M - X

[H₂O] = 0.500M - X

[CO₂] = X

[H₂] = X

<em>Where X is reaction coordinate. The amount of reactant that reacts producing products.</em>

<em />

Replacing in Kc expression:

1.845 = [CO₂] [H₂] / [CO] [H₂O]

1.845 = [X] [X] / [0.500M - X] [0.500M - X]

1.845 = X² / X² - X + 0.25

1.845X² - 1.845X + 0.46125 = X²

0.845X² - 1.845X + 0.46125 = 0

Solving for X:

X = 0.288M; Right solution

X = 1.9M; False solution: Produce negative concentrations.

Replacing, equilibrium concentrations are:

[CO] = 0.500M - X = 0.212M

[H₂O] = 0.500M - X = 0.212M

[CO₂] = X = 0.288M

[H₂] = X = 0.288M

3 0
3 years ago
Question 1-8
JulijaS [17]

If 28.0 grams of a gas occupies 22.4 liters at STP, the gas could be carbon monoxide, CO

<h3>Ideal gas </h3>

We understood from the ideal gas equation that 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP)

<h3>How to determine the identity of the gas</h3>

To determine the identity of the gas, we shall determine the mass of 1 mole of each gas. This can be obtained as

For C₂H₂

1 mole of C₂H₂ = (12×2) + (2×1) = 26 g

For C₂H₆

1 mole of C₂H₆ = (12×2) + (6×1) = 30 g

For CO₂

1 mole of CO₂ = 12 + (16×2) = 44 g

For CO

I mole of CO = 12 + 16 = 28 g

From the above illustrations, we can see that 1 mole of CO is equivalent to 28 g.

Thus, the correct answer to the question is CO

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

3 0
2 years ago
An unknown solution has a ph of 8. how would you classify this solution?
Delvig [45]
I believe the correct answer from the choices listed above is option C. You would classify this solution as basic since it has the pH of more than 7 which signifies a basic solution. Hope this answers the question. Have a nice day. Feel free to ask more questions.
6 0
4 years ago
What triggers the onset of estrus in most seasonal breeders
Anna11 [10]

Answer:

· Litter loss triggers estrus in a nonsocial seasonal breeder

Explanation:

6 0
3 years ago
23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate
Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

  • HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We <u>calculate the moles of HCl that reacted</u>, using the volume used and the concentration:

  • 32.27 mL ⇒ 32.27/1000 = 0.03227 L
  • 0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we <u>calculate the mass of NH₃ that was titrated</u>, using its molecular weight:

  • 3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

  • 0.0592 / 12.949 * 100% = 0.4575%

Now we <u>calculate the total mass of NH₃ in the diluted sample</u>:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

  • 0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

  • 0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃

6 0
3 years ago
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