Answer:
The correct answer is option C.
Explanation:
As it is given that, a Mendelian cross is performed between two parents resulted by cross the parents. This suggests that the parents or P generation has zero recombination hence the genotype of Parents would be AA and aa in nature. Therefore, all the F1 generation offspring were Aa in nature. The selfing of the F1 offspring will be:
A a
A AA Aa
a Aa aa
Genotype: AA: Aa: aa :: 1:2:1
Phenotype: Dominant: recessive :: 3:1
A. Kinetic energy is the energy of motion. B,C,D all describe situations where there is not movement.
The answer would be false. the correct answer would be stock <span />
Answer:
Transport vesicles will not be brought to either the Golgi apparatus or the plasma membrane.
Explanation:
Microtubules forms part of the structure of the cytoskeleton. It is a polymer of tubulins.
Apart from maintaining the cell structure, cytoskeleton plays a role in transportation in a cell.
A Constructive secretory pathway is an exocytosis process found in all eukaryotic cells, in which transport vesicles destined for the plasma membrane leave the trans-Golgi network in a steady stream
A disruption on microtubules will lead to a change in structure of the cytoplasm. It will not be able to perform its function therefore transport vesicles will not be brought to either the plasma membrane or the golgi apparatus.
The answer to this question is pyruvic acid.
This process is also known as the Embden-Meyerhof or glycolytic pathway and is undoubtedly the most common pathway for glucose degradation to pyruvate in the second stage of catabolism. It is found in all major groups of microorganisms and functions in the presence or absence of oxygen. Glycolysis occurs in the cytoplasmic matrix of prokaryotes and eukaryotes.
The pathway as a whole is divided into two parts: The initial 6 carbon stage and secondly, the 3 carbon stage.
One of the products, glyceraldehyde 3-phosphate, is converted directly to pyruvic acid in a five step process.
