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MrRissso [65]
4 years ago
14

G(x)=15x-10 inverse function with steps please​

Mathematics
1 answer:
Alexus [3.1K]4 years ago
4 0

Answer:

The inverse function is g(x) = 

\frac{x + 10}{15}

Step-by-step explanation:

You can find the inverse of any function by switching the g(x) value (or whatever the function value is labelled) and the x value. Then solve for the new g(x) value. The result will be your inverse function.

g(x) = 15x - 10 ---> Switch the g(x) and x

x = 15g(x) - 10 ---> Add 10 to both sides

x + 10 = 15g(x) ----> Divide both sides by 15.

\frac{x + 10}{15} = g(x) ----> Switch the order

= g(x) ----> Switch the order

g(x) =

\frac{x + 10}{15}

And that would be your inverse function.

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Answer:

99% of the sample means will fall between 0.93288 and 0.94112.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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This means that \mu = 0.9370, \sigma = 0.0090

Sample of 32:

This means that n = 32, s = \frac{0.009}{32} = 0.0016

Within what interval will 99 percent of the sample means fall?

Between the 50 - (99/2) = 0.5th percentile and the 50 + (99/2) = 99.5th percentile.

0.5th percentile:

X when Z has a pvalue of 0.005. So X when Z = -2.575.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2.575 = \frac{X - 0.9370}{0.0016}

X - 0.9370 = -2.575*0.0016

X = 0.93288

99.5th percentile:

X when Z has a pvalue of 0.995. So X when Z = 2.575.

Z = \frac{X - \mu}{s}

2.575 = \frac{X - 0.9370}{0.0016}

X - 0.9370 = 2.575*0.0016

X = 0.94112

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