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stepan [7]
3 years ago
10

What is the equation of the line in slope-intercept form?

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0

Answer:y = 3x/4 + 4

Step-by-step explanation:

The equation of a line in the slope-intercept form is represented by

y = mx + c

Where c = y-intercept

Slope, m = change in the value of y on the vertical axis / change in the value of x in the horizontal axis.

change in the value if y is y2 -y1 and change in the value of x is x2 - x1

Where

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the graph,

y2 = 4

y1=0

x2=0

x1 = -3

we can determine the slope.

Slope, m = (4-0) / (0- -3)

= 4/3

Let us pick points (0,4) to determine the intercept

Substituting x = 0 , y = 4 and m = 4/3 into the slope-intercept equation,

y = mx + c

4 = 3/4×0 + c

c = 4

Equation of the line in slope-intercept form is

y = 3x/4 + 4

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The potential solutions of log_4x+log_4(x+6)=2 are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

  • Product Rule for Logarithms - log_{b}(a*c)=log_{b}a+log_{b}c
  • Quotient Rule for Logarithms - log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c
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The exercise asks the potential solutions for  log_4x+log_4(x+6)=2. In this expression you can apply the Product Rule for Logarithms.

                                  log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0

Now you should solve the quadratic equation.

 

 Δ=b^2-4ac=36-4*1*(-16)=36+64=100. Thus, x will be x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}. Then:

x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8

The potential solutions  are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

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