Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Answer:
last option is the answer; all values greater than 12
Step-by-step explanation:
2/3x - 5 > 3
2/3x > 8
x > 24/2
x > 12
Step-by-step explanation:
line a is perpendicular to B.
if the slope of line A is -3/4 what is the line of B
<span>2 4/9 = 22/9
Area of square = a^2 = (22/9)^2 = 484/81 square inches.
hope that helps</span>
