we know the x-intercept of the line is 1, recall that an x-intercept is when the graph intercepts or touches the x-axis, and when that happens, y = 0, so the point is really x = 1, y = 0, namely (1,0). We also know another point on the line, is (-2, 9).

Answer:
129.6º
Step-by-step explanation:
7 + 10 + 2 + 6 + 11 = 36%
QAV = 36% * 360º = 129.6º
Answer:

Step-by-step explanation:
In order to find r we have to square both sides of the equation

The *square root* sign cancels out the *squared* sign therefore:

Answer:
i think the answer is 72
Step-by-step explanation: