F’(x)= -akxsinkx
F’’(x)= -a(kx)^2coskx
I’m really sorry if the answer turned out wrong but I tried my best!
Answer:
It lasted 116 years and saw many major battles – from the battle of Crécy in 1346 to the battle of Agincourt in 1415, which was a major English victory over the French.
Standard deviation is the square root of the variance. For the square root of a number to be greater than the number, the number must be between 0 and 1.
Hence, for the standard variation to be greater than the variance, the variance must be between 0 and 1.
Answer: C [0.75]
Answer:
Step-by-step explanation:
Let 
, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:
(1)
(2)
Now we perform the operations: 
(3)
By the quadratic formula, we find the following solutions:
and 
Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:
By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:
Then, the values of the cosine associated with that angle is:
Now, we have that 
, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:
(4)
(5)
If we know that and , then the value of the function is:
