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Maurinko [17]
2 years ago
13

Rooster + rooster + rooster =20

Mathematics
1 answer:
Leya [2.2K]2 years ago
6 0
If rooster = 6 eggs =10 banana = 5 and 6+10x5= 56
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Triangle ABC is similar to triangle PQR, as shown below:
natita [175]

Answer:

\frac{q}{b}=\frac{r}{c}

Step-by-step explanation:

Consider the options for this question are as follow,

  • \frac{q}{c}=\frac{r}{b}
  • \frac{c}{p}=\frac{b}{a}
  • \frac{c}{a}=\frac{q}{r}
  • \frac{q}{b}=\frac{r}{c}

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

\traingle ABC\sim \triangle PQR

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}

\frac{c}{r}=\frac{a}{p}=\frac{b}{q}

\frac{r}{c}=\frac{p}{a}=\frac{q}{b}

\implies \frac{q}{b}=\frac{r}{c}

3 0
3 years ago
Read 2 more answers
Find the length of the third side if necessary round to the nearest tenth
Fantom [35]

Answer:

8

Step-by-step explanation:

Let's call the missing side as x

Base on the pythagorean theorem, we have :
17² - 15² = x²

289 - 225 = x²

x² = 64

So, x equals 8.

Hope it helps

8 0
2 years ago
The work W required to move a particle from a far distance to within radius r of another particle varies jointly as the product
tangare [24]

Answer:

W = kq1q2 / r

Step-by-step explanation:

W varies jointly as the product of q1 and q2 and inversely as radius r

Product of q1 and q2 = q1q2

W = (k*q1"q2) / r

W = kq1q2 / r

Where,

W = work

q1 = particle 1

q2 = particle 2

r = radius

k = constant of proportionality

The answer is W = kq1q2 / r

5 0
3 years ago
Write L if it is likely to happen and U if unlikely to happen.
maria [59]

Answer:

Probabilities

        Likely to happen (L)      Unlikely to happen (U)

a.      4/5                                 5/8

b.     3/5                                  3/8

c.     4/5                                  4/7

d.    0.3                                  0.09

e.    5/6 and 4/5                   2/3

Step-by-step explanation:

Probabilities in Percentages:

a. The probability of 4/5 = 80% and 5/8 = 62.5%

b. The probability of 3/8 = 37.5% and 3/5 = 60%

c. The probability of 4/5 = 80% and 4/7 = 57%

d. The probability of 0.3 = 30% and 0.09 = 9%

e. The probability of 2/3 = 67% and 4/5 = 80% and 5/6 = 83%

b) To determine the relative values of the fractional probabilities, it is best to reduce them to their fractional or percentage terms.  When this is done, the relative sizes become obvious, and then, comparisons can be made.

3 0
2 years ago
An online retailer sells two packages of protein bars.
krok68 [10]
In order to find the price per bar, we divide the price by the amount of bars.  For the first one:

15.37/10 = $1.54 per bar

The second package:

15.35/12 = $1.28 per bar.

The 10-pack costs $1.54 per bar and the 12-pack costs $1.28 per bar.  The 12-pack has the better price per bar.

Now, let's look at the price per ounce.  We do this in a similar way.  We find the total amount of ounces in the package, and divide the price by the number of ounces.

In the first package, we multiply 10*2.1=21.  We have 21 ounces in the first package.  Now we divide 15.37/21.  In the first package, we have 0.73 dollars per ounce.

Now, let's look at the second package.  We start by multiplying 1.4*12=16.8.  There are 16.8 ounces in the package.  Now, we divide 15.35/16.8=0.91.  So, in the second package, we have 0.91 dollars per ounce.

The cost per ounce of the 10-pack is $0.73 and the cost per ounce of the 12-pack is $0.91.  The first package has the better price per ounce.

The better explanation is the second one, because I prefer the lower price per ounce, I think that the 1st pack is the better buy.
5 0
3 years ago
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