Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
Answer:
x>−7
Step-by-step explanation:
left side:
-8(x-3)+5x
distribute -8 into (x-3)
-8x+24+5x
combine like terms
-3x+24
right side:
9(x+12)
distribute 9 into (x+12)
9x+108
-3x+24<9x+108
Subtract 24 on both sides
-3x< 9x+108-24
combine like terms
-3x<9x+84
Subtract 9x on both sides
-3x-9x<+84
combine like terms again
-12x<84
Multiply both sides by -1 (reverse the inequality)
(-12x)(-1)>84(-1)
12x>-84
divide both sides with 12

x>−7
hope this helps
The answer would be n<4 because 4 is greater than n.
Answer:
you are my idol
Step-by-step explanation:
Keep working. Karma is real
Answer:
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