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ollegr [7]
3 years ago
7

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

xam has a standard deviation that is less than 5.0 minutes. A random sample of 15 students was selected and the sample standard deviation for the time needed to complete the exam was found to be 4.0 minutes. Using α = 0.05, the conclusion for this hypothesis test would be that because the test statistic is
Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

n=15 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =16 represent the sample variance

\sigma^2_0 =25 represent the value that we want to  verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And replacing we got:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

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Answer:

12 + 20d

Step-by-step explanation:

OG fare = 12

Ticket price =d

20 Tickets =20d

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the number 792 and 990, written as the product of their prime factors are 792 = 23 x 32 x 11 and 990 = 2 x 9 x 5 x 1. Hence, fin
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198

Step-by-step explanation:

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A+B = 30. A:B is equivalent to 2:3. Find two whole numbers that satisfy the two conditions.
Valentin [98]
I think the 2 numbers would be 12 and 18. Hope this helps.
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3 years ago
A survey of high schools offering honors classes to ninth graders reveals that 38% of the high schools offer no honors classes,
Greeley [361]

Using the discrete distribution, it is found that the probability that it offers an even number of honors classes is of 0.68.

<h3>What is the discrete probability distribution?</h3>

The distribution for the number of honors classes the school offers is given by:

  • P(X = 0) = 0.38
  • P(X = 1) = 0.12.
  • P(X = 2) = 0.25.
  • P(X = 3) = 0.2.
  • P(X = 4) = 0.05.

Hence the probability of an even number is given by:

P(even) = P(X = 0) + P(X = 2) + P(X = 4) = 0.38 + 0.25 + 0.05 = 0.68.

More can be learned about discrete probability distributions at brainly.com/question/24802582

#SPJ1

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a nutrition major at wright state was studying the relationship between carbohydrates (x) and calories (y). for example, a servi
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Answer:

The predicted calories would be 403 calories.

Step-by-step explanation:

We have a linear regression model relating y: calories with x: carbohydrates, which has a slope of 4.0 and a y-intercept of 3.0.

Then, the model equation is:

y=4.0x+3.0

With these model we can predict the calories values for any amount of carbohydrates, within the interval within which this model is valid.

If a new food is tested, and the number of carbohydrates (x) is 100, the predicted value will be:

y(100)=4.0(100)+3.0=400+3=403

The predicted calories would be 403 calories.

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2 years ago
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