Parenthises
Exponent
Multiply
Divide
Add
Subtract
The answer is true because it comes before subtraction in the phrase PEMDAS.
Answer:
B and C work. A and D do not.
Step-by-step explanation:
This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.
A]
5n + 6
Let n = 1
5(1) + 6
5 + 6= 11
However there is trouble beginning with n = 2
5*2 + 6
10 + 6
16 All you need is one wrong answer and the choice is toast. So A won't work.
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Try D
6(n - 1)+ 5
n=0
6*(-1) + 5
-6 + 5
- 1
And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse. D is not one of the answers.
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B
Let n = 1
6(1) + 5
6 + 5
11 The first term works.
n = 2
6*(2) + 5
12 + 5
17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.
n = 3
6*(3) + 5
18 + 5
23 And this also works. I'll let you deal with n = 4
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C
n = 0
6(0 + 1) + 5
6*1 + 5
6 + 5
11
n = 1
6(1 + 1) + 5
6*2 + 5
12 + 5
17 which works.
So C is an answer.
Answer:
5x4x3=60
Step-by-step explanation:they are because when you simplify they are the same
Among the choices, the statement which describes a skewed histogram showing a distribution of the weights of students in a class is:
<span>"The nature of the skew can be verified by the position of the mean with respect to the mode."
The histogram is skewed to the right if the mean is less than the mode and the histogram is skewed to the left if the mean is more than the mode. </span><span />
Answer:
2
Step-by-step explanation:
For any positive numbers a,b we always have the following identity:
(gcd(a,b) denotes the greatest common divisor between a and b, and lcm(a,b) denotes the least common multiple between a and b)
In our case, we are given that 
and that 
. Plugging that in into our identity, we get:
And so solving for 
:
